Bagaimana Anda menyelesaikan 4x² - 4x - 1 = 0?

Bagaimana Anda menyelesaikan 4x² - 4x - 1 = 0?
Anonim

Menjawab:

# x = (1 + sqrt2) / (2) #

Penjelasan:

#color (blue) (4x ^ 2-4x-1 = 0 #

Ini adalah persamaan Quadratic (dalam bentuk # ax ^ 2 + bx + c = 0 #)

Gunakan rumus kuadratik

#color (brown) (x = (- b + -sqrt (b ^ 2-4ac)) / (2a) #

Dimana

#color (red) (a = 4, b = -4, c = -1 #

#rarrx = (- (- 4) + - sqrt (-4 ^ 2-4 (4) (- 1))) / (2 (4)) #

# rarrx = (4 + -sqrt (-4 ^ 2-4 (4) (- 1))) / (8) #

# rarrx = (4 + -sqrt (16 - (- 16))) / (8) #

# rarrx = (4 + -sqrt (16 + 16)) / (8) #

# rarrx = (4 + -sqrt (32)) / (8) #

# rarrx = (4 + -sqrt (16 * 2)) / (8) #

# rarrx = (4 + -4sqrt2) / (8) #

# rarrx = (batal (4) ^ 1 + -batal (4) ^ 1sqrt2) / (batal8) ^ 2 #

#color (hijau) (rArrx = (1 + -sqrt2) / (2) #