Bagaimana Anda memverifikasi (tan ^ 2x) / (secx-1) -1 = secx?

Bagaimana Anda memverifikasi (tan ^ 2x) / (secx-1) -1 = secx?
Anonim

# "Sisi Kiri" = tan ^ 2x / (secx-1) -1 #

Gunakan identitas: # cos ^ 2x + sin ^ 2x = 1 #

# => 1 + tan ^ 2x = dtk ^ 2x #

# => tan ^ 2x = dtk ^ 2x-1 #

# => "Sisi Kiri" = (dtk 2x-1) / (dtk-1) -1 = (batal ((dtx-1)) (dtk + 1)) / batalkan (secx-1) -1 #

# => secx + 1-1 = warna (biru) secx = "Sisi Kanan" #