Misalkan f (x) = 3x +1 dengan f: R -> R. Temukan fungsi linier h: R -> R sedemikian rupa sehingga: h (f (x)) = 6x - 1?

Menjawab:

#h (x) = 2x-3 #

Penjelasan:

# "sejak" h (x) "adalah fungsi linear" #

# "let" h (x) = ax + b #

#rArrh (f (x)) = a (3x + 1) + b #

#color (white) (rArrh (f (x))) = 3ax + a + b #

.# "sekarang" h (f (x)) = 6x-1 #

# rArr3ax + a + b = 6x-1 #

#color (blue) "bandingkan koefisien istilah seperti" #

# rArr3a = 6rArra = 2 #

# a + b = -1rArr2 + b = -1rArrb = -3 #

#rArrh (x) = kapak + b = 2x-3 #