Apa itu (x ^ -3) ^ 2 * x ^ 5 / x ^ -1?

Menjawab:

#1#

Penjelasan:

# (x ^ -3) ^ 2 * x ^ 5 / x ^ -1 = x ^ (- 3 * 2) * x ^ 5 * x ^ 1 = x ^ -6 * x ^ 6 = x ^ 6 / x ^ 6 = 1 #

Menjawab:

#1#

Terapkan hukum indeks

Penjelasan:

# (x ^ -3) ^ 2 xx x ^ 5 / x ^ -1 "" larr (x ^ m) ^ n = x ^ (mn) #

# = x ^ -6 xx x ^ 5 / x ^ -1 "" larr x ^ -m = 1 / x ^ m #

# = 1 / x ^ 6 xx x ^ 5 xx x ^ 1 "" larr x ^ m xx x ^ n = x ^ (m + n) #

# = x ^ 6 / x ^ 6 #

# = x ^ 0 "" larr x ^ m / x ^ n = x ^ (m-n) #

# = 1 "" larr x ^ 0 = 1 #

Menjawab:

#color (magenta) (= 1 #

Penjelasan:

# (x ^ (- 3)) ^ 2 x ^ 5 / x ^ (- 1 #

# "Menerapkan hukum:" # #color (blue) ((a ^ m) ^ n = a ^ (mn; #

# = x ^ (- 3xx2) x ^ 5 / x ^ (- 1 #

# = x ^ (- 6) x ^ 5 / x ^ (- 1 #

# "Menerapkan hukum:" # #warna (biru) (a ^ m / a ^ n = a ^ (m-n) #

# = x ^ (- 6) x ^ (5 - (- 1)) #

# = x ^ -6 x ^ 6 #

# "Menerapkan hukum:" # #color (biru) (a ^ m a ^ n = a ^ (m + n); "#

# = x ^ (- 6 + 6) #

# = x ^ 0 #

# "Menerapkan hukum:" # #color (blue) (a ^ 0 = 1 #

#color (magenta) (x ^ 0 = 1 #

#-"Semoga ini membantu!:)"#