Menjawab:
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))))) ((1) / ((x + 4)))). (((x) ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 + 4) (ln (x ^ 2 + 4)))) #
Penjelasan:
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))))) (1 / (x + 4) / (ln (x ^ 2 + 4)))). (((1) (ln (x ^ 2 + 4)) - (x + 4) (1) / ((x ^ 2 + 4)) (2x)) / ((ln (x ^ 2 + 4))) ^ 2) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))))) (ln (x ^ 2 + 4) / ((x + 4)))). ((ln (x ^ 2 + 4) - (2x ^ 2 + 4x) / ((x ^ 2 + 4))) / ((ln (x ^ 2 + 4))) ^ 2) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))))) (membatalkan (ln (x ^ 2 + 4)) / / ((x + 4))). (((x ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 + 4) (ln (x ^ 2 + 4)) ^ membatalkan (2))) #
#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))))) ((1) / ((x + 4)))). (((x) ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 + 4) (ln (x ^ 2 + 4)))) #
