Apa titik puncak y = (x + 2) ^ 2 + 3x + 4?

Apa titik puncak y = (x + 2) ^ 2 + 3x + 4?
Anonim

Menjawab:

# "Vertex {-3.5", "-4.25} #

Penjelasan:

# y = (x + 2) ^ 2 + 3x + 4 #

# y = x ^ 2 + 4x + 4 + 3x + 4 #

# y = x ^ 2 + 7x + 8 "(1)" #

# (d y) / (d x) = 0 #

# (d y) / (d x) = 2x + 7 = 0 #

# 2x + 7 = 0 #

# 2x = -7 #

# x = -7 / 2 = -3.5 #

# "gunakan (1)" #

#y = (- 7/2) ^ 2-7 (7/2) + 8 #

# y = 49 / 4-49 / 2 + 8 #

# y = (49-98 + 32) / 4 #

# y = -17 / 4 = -4.25 #

# "Vertex {-3.5", "-4.25} #